# How are stator losses calculated?

Contents

## What are stator losses?

= Stator Resistance The stator losses are a function of the stator winding resistance and directly proportional to square of stator currents, thus stator losses are inversely proportional to square of efficiency and power factor.

## How are rotor losses calculated?

The rotor copper loss is calculated by subtracting the stator copper loss from the total measured loss or the rotor I2R loss. The friction and windage loss may be assumed constant, irrespective of the load.

Losses Calculation

1. Core loss in the stator and the rotor.
2. Stator and rotor copper losses.
3. Friction and windage loss.

## What is copper loss formula?

Copper loss calculation formula:

Copper loss Pc in Watts is equal to the resistance R(Ω) in ohms times of the square of the current I(A) in Amps. But the transformer has two winding such as primary winding and secondary winding. … R2(Ω) = Secondary resistance in ohms.

## Which losses are fixed losses?

Intrinsic losses are of two types: fixed losses – independent of motor load, and variable losses – dependent on load. Fixed losses consist of magnetic core losses and friction and windage losses. Magnetic core losses (sometimes called iron losses) consist of eddy current and hysteresis losses in the stator.

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## What is slip formula?

Slip speed is the speed difference between the Synchronous speed and Rotor speed. Slip speed = Synchronous speed – Rotor speed = Ns -N. Slip, s = (Ns – N) / Ns.

## How many losses are present in induction motors?

Explanation: There are 5 losses present in the induction motor. They are i) Stator copper losses, ii) Rotor copper losses, iii) Stator iron losses, iv) Friction and winding losses, v) Additional losses.

## What is the ratio of rotor copper loss and rotor input?

In an induction motor, what is the ratio of rotor input to rotor copper loss? Rotor copper loss = S × Rotor input power ∴ Rotor input / Rotor copper loss = 1/S.

## What is the formula for calculation of rotor resistance?

Example 5.3

Step no. Total rotor circuit resistance RΩ Resistance between steps Ω
3 R23 = β · R22 = 0.676 × 0.435 = 0.294 0.294 – 0.199 = 0.095
4 R24 = β · R23 = 0.676 × 0.294 = 0.199 0.199 – 0.135 = 0.064
5 R25 = β · R24 = 0.676 × 0.199 = 0.135 0.135 – 0.09 = 0.045
6 R2 = 0.09 = 0.09 0.09 – 0 = 0.090

## What are core losses and copper losses?

Copper loss is the term often given to heat produced by electrical currents in the conductors of transformer windings, or other electrical devices. Copper losses are an undesirable transfer of energy, as are core losses, which result from induced currents in adjacent components.